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C program to swap two numbers without using third variable and using functions
Posted: May 19, 2017 11:22 AM
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C program to swap two numbers using functions temporary variable. We can swap two numbers by using temporary variable. Lets see an example C program to swap two numbers without using any function. C program to swap two numbers using third variable
Program #1: Write a C program to swap two numbers using temporary variable without using any function and by using third variable. #include <stdio.h> #include <stdlib.h> int main(int argc, char *argv[]) { int a,b, temp; printf("Please enter two integer number to swap\n"); scanf("%d%d",&a,&b); printf("before swapping\n"); printf("a=%d\n",a); printf("b=%d",b); temp=a; a=b; b=temp; printf("\nafter swapping\n"); printf("a=%d\n",a); printf("b=%d",b); return 0; } Output: Program #2: Write a C program to swap two numbers using temporary variable with using function and using third variable. C program to swap two numbers using functions call by value #include <stdio.h> #include <stdlib.h> void swap(int a, int b); int main(int argc, char *argv[]) { int a,b; printf("Please enter two integer numbers to swap\n"); scanf("%d%d",&a,&b); printf("before swapping\n"); printf("a=%d\n",a); printf("b=%d",b); swap(a,b); return } void swap(int a, int b){ int temp=a; a=b; b=temp; printf("\nafter swapping\n"); printf("a=%d\n",a); printf("b=%d",b); } Output: Please enter two integer numbers to swap 10 20 before swapping a=10 b=20 after swapping a=20 b=10
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