Java Answers Forum - Exception Handling

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Exception Handling

2 replies on 1 page. Most recent reply: Jun 6, 2005 12:50 PM by Archie

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Archie

Posts: 2
Nickname: archie123
Registered: Jun, 2005

Exception Handling

Posted: Jun 5, 2005 3:04 PM

I want to modify the following program so that the user can continue entering strings after the exception message appears. How do I do that???

import java.util.Scanner;

public class StringTooLongExceptionDriver
{
public static void main(String[] args) throws StringTooLongException
{
String strInput;

StringTooLongException error = new StringTooLongException("String longer than 20 characters");

Scanner scan = new Scanner(System.in);

System.out.print ("Enter some characters (DONE to quit): ");
strInput = scan.nextLine();

while (!strInput.equals ("DONE"))
{
if (strInput.length() > 20)
throw error;

System.out.print ("Enter some characters (DONE to quit): ");
strInput = scan.nextLine();
}
}
}

public class StringTooLongException extends Exception
{
StringTooLongException (String message)
{
super (message);
}
}

Matthias Neumair

Posts: 660
Nickname: neumi
Registered: Sep, 2003

Re: Exception Handling

Posted: Jun 5, 2005 10:54 PM

The while statement must be outside the method wich throws the error.

{
  try {
    getUserInput(); //read String, throw Exception if String > 20
  } catch (StringTooLongException e) {
//    handle Exception
  }
} while (!endCondition);

Archie

Posts: 2
Nickname: archie123
Registered: Jun, 2005

Re: Exception Handling

Posted: Jun 6, 2005 12:50 PM

Thanks for your reply...it really helped!!!

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