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Rookie question on Boolean operators

1 reply on 1 page. Most recent reply: Aug 14, 2006 2:47 AM by Dave Hinton

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Guido

Posts: 38
Nickname: kiethb
Registered: May, 2002

Rookie question on Boolean operators

Posted: Aug 10, 2006 7:31 AM

Can someone please explain the difference between the following two snippets? I am using a short circuit && and a non-short circuited | at the same time to evaluate these conditions.


int x = 2; 
int y = 5; 
if (( x > 3 ) && ( y < 2 ) | boo() ){ 
       Print(“You got this right”); 
}  
public boolean boo(){   return true;  }

I understand that this logic is saying that x must be greater than 3 AND EITHER y has to be less than 2 OR boo must be true. weird but no problems there. however, in the following i have made a change to a short circuited OR...


int x = 2; 
int y = 5; 
if (( x > 3 ) && ( y < 2 ) || boo() ){ 
       Print(“You got this right”); 
}  
public boolean boo(){   return true;  }

Can someone tell me the logic of why this is being evaluated like there are now parenthesis around the first two arguments like this: ((x>3) && (y<2)) ??? this is how i would have thought the first example would have worked but to my dismay it did not. just having trouble visualizing the effects when mixing short circuits and non-shorties...

any help will be much appreciated! thanks!

Dave Hinton

Posts: 42
Nickname: catbells
Registered: Oct, 2003

Re: Rookie question on Boolean operators

Posted: Aug 14, 2006 2:47 AM

Different operators have different precedences. Find a java operator precedence table, you will find that these operators are in different places.

You have found that it is difficult to understand code that mixes boolean short-circuiting and non-short-circuiting operators in the same line… so don’t do it.

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