I am familiar with how to set up a Java program as a Windows service in Windows NT 4 and above. However, I'd like to learn how to do the same on Windows 98 SE and Windows ME. I'm not that familiar with Windows, so any help would be appreciated. I understand that in Win98 and ME, you'd have to have a registry key for the application that tells the OS to start up a specific program when the machine boots up. Are those the same as a system service?
Did you try the AutoExec.bat file? I am not sure whether I understood your question properly but I geuss you have problem setting the path. Open your AutoExec.bat file with notepad (Win98 or ME) and then add this... set path="[jdk path]\bin"; E.g. set path="C:\JDK\bin";
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