The Artima Developer Community
Sponsored Link

Java Answers Forum
I have got a tricky algorithm to write

0 replies on 1 page.

Welcome Guest
  Sign In

Go back to the topic listing  Back to Topic List Click to reply to this topic  Reply to this Topic Click to search messages in this forum  Search Forum Click for a threaded view of the topic  Threaded View   
Previous Topic   Next Topic
Flat View: This topic has 0 replies on 1 page
nes

Posts: 137
Nickname: nn
Registered: Jul, 2004

I have got a tricky algorithm to write Posted: Dec 5, 2005 6:07 PM
Reply to this message Reply
Advertisement
I currently have a tricky problem at work to write an algorithm for. I googled around a bit, but "time intervals" did not come up with anything useful. Although I have some rough idea of how I could solve it, I still would value some input.

I have information of (It has only couple dozen entries.)
ServiceNum, DollarCost

and a input database table in the form (several GBytes):
ClientNumber (CN), BeginDate(BD), EndDate(ED), ServiceNumber_Purchased(SN)
--Date intervals are always [closed, closed]

The output is:
ClientNumber(CN), BeginDate(BD), Enddate(ED), DollarCost(DC)

With the following requirements:
1) The input dates can be overlapping dates.
The output has to be non-overlapping "broken up" dates

Example: (assuming SN 1=$10 and SN 2=$20)
input (CN, BD, ED ,SN):
10, 1/1/2001,1/1/2005,1
10, 1/1/2002,1/1/2004,2

should result in:
output (CN, BD, ED, DC):
10, 1/1/2001, 12/31/2001, $10
10, 1/1/2002, 1/1/2004, $30
10, 1/2,2004, 1/1/2005, $10

2) if the same service is purchased twice for an interval it should be billed only once. Example:
input:
10, 1/1/2001, 1/1/2005, 1
10, 1/1/2004, 1/1/2007, 1

output:
10, 1/1/2001, 1/1/2007, $10

Here are my thoughts about a solution so far:

1. fetch the input data sorted by clientNumber, Begindate, Enddate and ServiceNumber

2. read the row, store as temporary good interval, then read another row

3. if new begin-date is bigger than previous good interval end-date (or previously saved end-date), output previous good interval, start new good interval

4. else create new good interval entry with good interval begin-date and current row begin-date, store good interval end-date into a list or something (so we always compare against smallest end-date).

5. Use "bitwise or" on a service bitfield to add services and caluate the total

As you can see my algorithm is a bit scetchy right now, but at this point I am more interested to determine the best data structure for the date interval problem (stack, queue, set,...).

nes

Topic: Callin Windows-DLL from java program Previous Topic   Next Topic Topic: please help me........

Sponsored Links



Google
  Web Artima.com   

Copyright © 1996-2019 Artima, Inc. All Rights Reserved. - Privacy Policy - Terms of Use