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simple array problem

4 replies on 1 page. Most recent reply: Mar 17, 2003 3:55 AM by Timsy

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Nilkanth

Posts: 4
Nickname: nilkanth
Registered: Mar, 2003

simple array problem

Posted: Mar 16, 2003 10:38 AM

Hi,
I've tokenize some lines and got some tokens. Now I wanna store those tokens in an array. Can someone help? Thanks.

Kishori Sharan

Posts: 211
Nickname: kishori
Registered: Feb, 2002

Re: simple array problem

Posted: Mar 16, 2003 12:56 PM

1. When you create tokenizer then get the total number of tokens.
2. Create an array of that size. You got size in step 1.
3. As you iterate using tokenizer keep storing the elements in your array.

Nilkanth

Posts: 4
Nickname: nilkanth
Registered: Mar, 2003

Re: simple array problem

Posted: Mar 16, 2003 3:00 PM

Hi Kishori,
Thanx for ur reply. Now I've store the tokens in the array. The tokens r something like:
hello this stay here come this go there 34 32.
Now I wanna find out if the token==this, then get the position of the before element, ie for 'hello' and 'come'. And if the token==this then convert the tokens following it in it's char value until next 'this' is hit. I tried something like:
if(allTheStrings[x].equals("this"))
System.out.println(allTheStrings[x-1]);
But this doesn't work. Can u pls advise? Thanks.

Kishori Sharan

Posts: 211
Nickname: kishori
Registered: Feb, 2002

Re: simple array problem

Posted: Mar 16, 2003 8:51 PM

Hi
The output of the program is not clear to me. Please describe the problem in details and also include the inputs and desired outputs of the program. I will try to solve it.

Thanks
Kishori

Timsy

Posts: 3
Nickname: timsy
Registered: Mar, 2003

Re: simple array problem

Posted: Mar 17, 2003 3:55 AM

public static void search1(String str){
StringTokenizer strTok = new StringTokenizer(str);
String temp;
int i = strTok.countTokens();
String strArr[] = new String;

for( i=0; strTok.hasMoreTokens(); i++){
strArr = strTok.nextToken();
}

for(i=0; i < strArr.length ; i++)
{
if (strArr.equals("this"))
{
System.out.println(strArr[i-1]);
}
}
}

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