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C program to print given number in words
Posted: May 19, 2017 7:22 PM
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Original Post: C program to print given number in words
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Write a program to input a digit and print it in words C program to print number in words using switch cas. Now we will see how to convert number /digits in to words in C programming. Get the input from the user using Scanf() function. Using while loop and % operator and get the each number and use switch case to print corresponding word for the current number.
Program #1: write a program in c that reads the digits and then converts them into words #include <stdio.h> #include <stdlib.h> int main(int argc, char *argv[]) { int number,i=0,j,digit; char * word[1000]; printf("Enter any integer to print that in words: "); scanf("%d",&number); while(number){ digit = number %10; number = number /10; switch(digit){ case 0: word[i++] = "zero"; break; case 1: word[i++] = "one"; break; case 2: word[i++] = "two"; break; case 3: word[i++] = "three"; break; case 4: word[i++] = "four"; break; case 5: word[i++] = "five"; break; case 6: word[i++] = "six"; break; case 7: word[i++] = "seven"; break; case 8: word[i++] = "eight"; break; case 9: word[i++] = "nine"; break; } } for(j=i-1;j>=0;j--){ printf("%s ",word[j]); } return 0; } Output:
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