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Learn how to validate objects in a boolean context without the usual harmful side effects.
In C++, there are a number of ways to
provide Boolean tests for classes. Such support is either provided to
make usage intuitive, to support generic programming, or both. We shall
examine four popular ways of adding support for the popular and idiomatic
if (object) {} construct. To conclude, we will discuss a new
solution, without the pitfalls and dangers of the other four.
Let the games begin.
Some types, for example pointers, allow us to test their validity in
Boolean contexts. Any rvalue of arithmetic, enumeration, pointer, or
pointer to member type, can be implicitly converted to an rvalue of type
bool. We frequently use this property to select a branch of code to
execute, for example when acquiring a resource:
if (some_type* p=get_some_type()) {
// p is valid, use it
}
else {
// p is not valid, take proper action
}
Of course, such usage is not only useful for built-in types; any type with an unambiguous meaning of validity could greatly benefit from such a Boolean conversion. The alternative is to use a member function for testing. As an example, consider testing a smart pointer (without an implicit conversion to the contained pointer) for validity:
smart_ptr<some_type> p(get_some_type());
if (p.is_valid()) {
// p is valid, use it
}
else {
// p is not valid, take proper action
}
Besides being more verbose, this version differs from the previous in
that the name p needs to be declared outside of the scope in which it is
used. This is bad from a maintenance perspective. Also, the name
is_valid will probably differ depending on the type of smart
pointer at use�it can just as well be is_empty,
Empty, Valid, or any other name a creative
designer might have thought of when creating it. Finally, even when
disregarding the naming issue and the problem with declaration scope, for
smart pointers there's the very real requirement to support pointer-like
use. It should typically be possible to convert existing code to make use
of smart pointers rather than raw pointers, with a minimum of change to
the code base, e.g., code like this should work regardless of pointer
smartness:
template <typename T> void some_func(const T& t) {
if (t)
t->print();
}
Without some conversion to a Boolean testable type, the above
if-statement won't compile for smart pointers. The goal that
we set out to accomplish in this article is making that conversion safe.
As we shall see, that's a bit harder than one would imagine at first
glance.
operator bool This classical approach has a straightforward implementation. I'll
use the same class (Testable) throughout this article, as
seen in the following code:
// operator bool version
class Testable {
bool ok_;
public:
explicit Testable(bool b=true):ok_(b) {}
operator bool() const {
return ok_;
}
};
// operator! version
class Testable {
bool not_ok_;
public:
explicit Testable(bool b=true):not_ok_(!b) {}
bool operator!() const {
return not_ok_;
}
};
// operator void* version
class Testable {
bool ok_;
public:
explicit Testable(bool b=true):ok_(b) {}
operator void*() const {
return ok_==true ? this : 0;
}
};
// nested class version
class Testable {
bool ok_;
public:
explicit Testable(bool b=true):ok_(b) {}
class nested_class {};
operator const nested_class*() const {
return ok_ ? reinterpret_cast<const nested_class*>(this) : 0;
}
};
Note the implementation for the conversion function:
operator bool() const {
return ok_;
}
Now, we can use instances of the class in expressions like this:
Testable test;
if (test)
std::cout << "Yes, test is working!\n";
else
std::cout << "No, test is not working!\n";
That's fine, but there's a nasty caveat to this as the conversion function has just told the compiler that it's free to do things behind our backs (lesson 0: never trust a compiler to do your job for you; at least not to do it properly);
test << 1; int i=test;
These are both nonsense operations, but yet allowed and legal C++ (we
also have the issue of overloading to consider, which makes things even
worse). So, operator bool is not a very good approach.
We're also able to compare any types that utilize this technique with each
other, although that rarely makes sense:
Testable a;
AnotherTestable b;
if (a==b) {
}
if (a<b) {
}
What else can we do? Well, one improvement is to add another
(private) conversion function to an integral type, and thereby disallow
the nonsensical operations, even those for equality and ordering. Simply
declaring a private conversion function to int does the
trick. However, some drawbacks remain, making the solution less than
satisfactory. The error messages when a user invokes the ambiguity aren't
consistent, or readable. Also, these conversion functions may interfere
with perfectly valid conversions and overloads. So we must look elsewhere
for a clean solution to this problem.
operator! It's time to move on to safer ground, through operator!.
Programmers are already accustomed to using this unary logical negation
operator in Boolean contexts, which is a desirable property for intuitive
usage. Still, some users might not be ready for what some people call the
double-bang trick (see below), which is a requirement for
checking the "good state" of such an object. The implementation is
trivial:
bool operator!() const {
return !ok_;
}
This is a much better approach—no more implicit conversion or
overloading issues to worry about, and two idiomatic ways of testing
Testable:
Testable test;
if (!!test)
std::cout << "Yes, test is working!\n";
if (!test2) {
std::cout << "No, test2 is not working!\n";
The first version utilizes a useful trick: if (!!test).
It's sometimes called the double-bang trick [1], but alas,
it is not nearly as elegant or straightforward as if (test).
[Editor's note: This is an old C trick used to map non-zero values to
the number 1 so you can have numeric integer values map into a
binary-valued index (0 or 1) for use with an array of size two] This
is a pity, because if people don't understand how something works it
really doesn't matter whether it's safe or not. It's still a very useful
technique, but it will typically be used in library code, where �ordinary�
users never see it. Of course, it's still possible to compare different
types, just as was the case with the first approach (although the obscure
syntax should make it obvious that it rarely makes sense to do so). Are
there better ways than this?
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