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How to find the max produce price or min product price using Java 8 Stream | Java 8 streams tutorial

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Ram N

Posts: 2777
Nickname: ramram
Registered: Jul, 2014

Ram N is Java Programmer
How to find the max produce price or min product price using Java 8 Stream | Java 8 streams tutorial Posted: Jul 12, 2017 8:31 AM
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This post originated from an RSS feed registered with Java Buzz by Ram N.
Original Post: How to find the max produce price or min product price using Java 8 Stream | Java 8 streams tutorial
Feed Title: JAVA EE
Feed URL: http://ramj2ee.blogspot.com/feeds/posts/default?alt=rss
Feed Description: This blog has viedo tutorials and Sample codes related to below Technologies. 1.J2EE 2.Java 3.Spring 4.Hibernate 5.Database 6.Oracle 7.Mysql 8.Design Patterns
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Product.java
class Product
{
private int id;
private String name;
private int price;

public Product(int id, String name, int price)
{
super();
this.id = id;
this.name = name;
this.price = price;
}

public int getId()
{
return id;
}

public void setId(int id)
{
this.id = id;
}

public String getName()
{
return name;
}

public void setName(String name)
{
this.name = name;
}

public int getPrice()
{
return price;
}

public void setPrice(int price)
{
this.price = price;
}

@Override
public String toString()
{
return "Product [id=" + id + ", name=" + name + ", price="
+ price + "]";
}

}
StreamDemo.java
import java.util.ArrayList;
import java.util.List;

/**
*
* Find Max and Min Product Price.
*
*/

public class StreamDemo
{
public static void main(String[] args)
{
List<Product> productList = new ArrayList<Product>();

// Adding Products
productList.add(new Product(1, "Sony mobile", 25000));
productList.add(new Product(2, "Lenovo mobile", 15000));
productList.add(new Product(3, "Nokia mobile", 10000));
productList.add(new Product(4, "Samsung mobile", 40000));


// max() method to get max Product price
Product maxPriceProduct = productList.stream()
.max((product1, product2)->
product1.getPrice() > product2.getPrice() ? 1: -1).get();

System.out.println("Max price product = "+maxPriceProduct);


// min() method to get min Product price
Product minPriceProduct = productList.stream()
.min((product1, product2)->
product1.getPrice() > product2.getPrice() ? 1: -1).get();

System.out.println("Min price product = "+minPriceProduct);

}
}
Output
Max price product = Product [id=4, name=Samsung mobile, price=40000]
Min price product = Product [id=3, name=Nokia mobile, price=10000]

Click the below link to download the code:
https://sites.google.com/site/ramj2eev1/home/javabasics/StreamDemo_productList_Max_Min_App.zip?attredirects=0&d=1

Github Link:
https://github.com/ramram43210/Java/tree/master/BasicJava/StreamDemo_productList_Max_Min_App

Bitbucket Link:
https://bitbucket.org/ramram43210/java/src/64bafbc8f43e8865b0cd21a106383d7ae583fbc8/BasicJava/StreamDemo_productList_Max_Min_App/?at=master

See also:

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  • Servlets Tutorial
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  • Java Collection Framework Tutorial
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  • Read: How to find the max produce price or min product price using Java 8 Stream | Java 8 streams tutorial

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